cos x sin x cos 2x
cos^2x-sin^2x= -cosx# #cos 2x= cos (- x)# #=> 2x = -x => 3x = 0 ,x = 0# Right this is a definite solution. Lets go back to the equation #2cos^2 x - 1 = - cos x# Bring everything over to one side. Let # cos x = a# #2a^2 + a -1 = 0# Factoring you get #(2a -1)(a + 1) = 0# #2a - 1 = 0# #a = 1/2#
Now that we have derived cos2x = cos 2 x - sin 2 x, we will derive cos2x in terms of tan x. We will use a few trigonometric identities and trigonometric formulas such as cos2x = cos 2 x - sin 2 x, cos 2 x + sin 2 x = 1, and tan x = sin x/ cos x. We have, cos2x = cos 2 x - sin 2 x = (cos 2 x - sin 2 x)/1 = (cos 2 x - sin 2 x)/( cos 2 x + sin 2 x) [Because cos 2 x + sin 2 x = 1]. Divide the
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Solvethe Following Equation: Cosx + Sin X = Cos 2x + Sin 2x . Department of Pre-University Education, Karnataka PUC Karnataka Science Class 11. Textbook Solutions 10542. Important Solutions 3. Question Bank Solutions 5825. Concept Notes & Videos 688 Syllabus. Advertisement Remove
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Precalculus Examples Popular Problems Precalculus Simplify sin2x/cosx Step 1Apply the sine double-angle 2Cancel the common factor of .Tap for more steps...Step the common by .
cos x sin x cos 2x